It is currently Tue Oct 17, 2017 7:46 am

 3 posts • Page 1 of 1
Author Message
x(x-y)
 Post subject: Volumes of Revolution Question  |  Posted: Wed Nov 23, 2011 10:54 pm

Original Member

Joined: Sat Aug 06, 2011 3:44 pm
Posts: 298
Location: UK

 Not to sound cocky, but I rarely get stuck on homework questions but this one (from the "OCR Advanced Mathematics Core 3 and 4" book, just in-case you're wondering) has got me scratching my head:"The region enclosed by both axes, the line x = 2 and the curve$\displaystyle y=\frac{1}{8}x^{2} + 2$is rotated about the y-axis to form a solid. Find the volume of this solid".NOTE: The answer, according to the back of the book, is $\displaystyle 9\pi$So, this is what I've done so far... Sorry if I've made an obvious mistake...$\displaystyle x = 2 \Rightarrow y = \frac{1}{8}(2)^2 + 2 = \frac{5}{2}$$\displaystyle 8(y-2)^{\frac{1}{2}} = x$$ \displaystyle V = \int_{0}^{\frac{5}{2}} \pi [8(y-2)]\: dy - \int_{0}^{\frac{5}{2}} \pi 2^2 \: dy$$\displaystyle \Rightarrow V = \int_{0}^{\frac{5}{2}} \pi (8(y-2) - 4) \: dy$$ \displaystyle \Rightarrow \pi [4(y-2)^2 - 4y];\frac{5}{2}, 0$... which does not give $\displaystyle 9\pi$ as an answer for a Volume.NOTE: I've attempted this many different ways, including subtracting the total volume of the "cuboidal area" from the answers obtained from integrating- but not to any avail!Any help is appreciated, thanks! _________________"Nature doesn't care what we call it, she just does it anyway".- Feynman
DrRocket
 Post subject: Re: Volumes of Revolution Question  |  Posted: Thu Nov 24, 2011 8:39 am
Original Member

Joined: Fri Aug 05, 2011 2:22 am
Posts: 477

 x(x-y) wrote:Not to sound cocky, but I rarely get stuck on homework questions but this one (from the "OCR Advanced Mathematics Core 3 and 4" book, just in-case you're wondering) has got me scratching my head:"The region enclosed by both axes, the line x = 2 and the curve$\displaystyle y=\frac{1}{8}x^{2} + 2$is rotated about the y-axis to form a solid. Find the volume of this solid".You were on the right track but you got the sign and the integral wrong. $\displaystyle Vol = \pi \times 2^2 \times \frac {5}{2} - \int_2^{\frac{5}{2}} 8 \pi (y-2) dy = 9 \pi$ _________________gone
x(x-y)
 Post subject: Re: Volumes of Revolution Question  |  Posted: Thu Nov 24, 2011 12:14 pm

Original Member

Joined: Sat Aug 06, 2011 3:44 pm
Posts: 298
Location: UK

 Ah yes, I see now- thanks for the help! I drew the graph quickly too- which helped to see what the solid of revolution would actually look like. _________________"Nature doesn't care what we call it, she just does it anyway".- Feynman
 Display posts from previous: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by AuthorPost timeSubject AscendingDescending
 3 posts • Page 1 of 1

Who is online
 Users browsing this forum: No registered users and 0 guests You cannot post new topics in this forumYou cannot reply to topics in this forumYou cannot edit your posts in this forumYou cannot delete your posts in this forum